Use the following Media4Math resources with this Illustrative Math lesson.
Thumbnail Image | Title | Body | Curriculum Nodes |
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Math Example--Volume Concepts--Calculating Volume: Example 3 | Math Example--Volume Concepts--Calculating Volume: Example 3TopicVolume DescriptionA hollow rectangular prism with outer dimensions: length = 60, width = 20, and height = 16. The inner hollow part has dimensions: length = 60, width = 18, and height = 14. The image shows how to subtract volumes to find the hollow volume. This image illustrates Example 3: The caption explains how to calculate the volume of a hollow rectangular prism by subtracting the inner volume from the outer volume. V = (60 * 20 * 16) - (60 * 18 * 14) = 4080. |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 4 | Math Example--Volume Concepts--Calculating Volume: Example 4TopicVolume DescriptionA hollow rectangular prism with outer dimensions labeled as x, y, and z, and inner hollow dimensions labeled as x - 2 and y - 2. The image shows a symbolic calculation for finding the hollow volume using variables. This image illustrates Example 4: The caption describes how to calculate the volume of a hollow rectangular prism by subtracting the inner volume from the outer volume using variables: V = xyz - z(y - 2)(x - 2) = 2z(y + x - 2). |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 5 | Math Example--Volume Concepts--Calculating Volume: Example 5TopicVolume DescriptionThe image shows a triangular prism with dimensions labeled as base (7), height (10), and length (25). It is part of an example on how to calculate the volume of a solid triangular prism. This image illustrates Example 5: "Find the volume of this triangular prism." The solution involves substituting the given measurements into the volume formula for a triangular prism: V = 1/2 * b * h * l = 1/2 * 7 * 10 * 25 = 875. |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 6 | Math Example--Volume Concepts--Calculating Volume: Example 6TopicVolume DescriptionThe image depicts a triangular prism with dimensions labeled as x, y, and z. The example demonstrates how to calculate the volume using a general formula for a triangular prism. This image illustrates Example 6: "Find the volume of this triangular prism." The solution uses the formula V = 1/2 * b * h * l, which is simplified to V = 1/2 * x * y * z.. |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 7 | Math Example--Volume Concepts--Calculating Volume: Example 7TopicVolume DescriptionThe image shows a hollow triangular prism with outer dimensions labeled as base (10), height (7), and length (35), and inner dimensions labeled as base (8) and height (5). The example calculates the volume by subtracting the hollow region from the full prism. This image illustrates Example 7: "Find the volume of this hollow triangular prism." The solution calculates the full volume using V = 1/2 * b1 * h1 * l1 - 1/2 * b2 * h2 * l2, which simplifies to V = 1/2 * 10 * 7 * 35 - 1/2 * 8 * 5 * 35 = 525.. |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 8 | Math Example--Volume Concepts--Calculating Volume: Example 8TopicVolume DescriptionThis image shows a hollow triangular prism with outer dimensions labeled as x, y, and z, and inner dimensions reduced by 2 units each. It demonstrates how to calculate the volume by subtracting the hollow region from the full prism. This image illustrates Example 8: "Find the volume of this hollow triangular prism." The solution uses V = 1/2 * b1 * h1 * l1 - 1/2 * b2 * h2 * l2, which simplifies to V = z(xy - (x - 2)(y - 2)) = z(x + y - 2).. |
Volume | |
Math Example--Volume Concepts--Calculating Volume: Example 9 | Math Example--Volume Concepts--Calculating Volume: Example 9TopicVolume Description
A green cylinder with a radius of 10 units and a height of 8 units. The radius is marked on the top surface, and the height is marked on the side. This image illustrates Example 9: The task is to find the volume of the cylinder. The volume formula V = πr2h is used. Substituting the values r = 10 and h = 8, the volume is calculated as V= 800π. |
Volume | |
MATH EXAMPLES--Teacher's Guide: Surface Area | MATH EXAMPLES--Teacher's Guide: Surface Area
This Teacher's Guide provides an overview of the 24 worked-out examples that show how to calculate the surface area of different three-dimensional figures. This is part of a collection of teacher's guides. To see the complete collection of teacher's guides, click on this link. Note: The download is a PDF file.Related ResourcesTo see resources related to this topic click on the Related Resources tab above. |
Surface Area | |
MATH EXAMPLES--Teacher's Guide: Volume | MATH EXAMPLES--Teacher's Guide: Volume
This set of tutorials provides 24 examples of how to find the volume of various 3-dimensional geometric figures. This is part of a collection of teacher's guides. To see the complete collection of teacher's guides, click on this link. Note: The download is a PDF file.Related ResourcesTo see resources related to this topic click on the Related Resources tab above. |
Volume | |
MATH EXAMPLES--Volume | MATH EXAMPLES--Volume
This set of tutorials provides 24 examples of how to find the volume of various 3-dimensional geometric figures. NOTE: The download is a PPT file. |
Volume | |
Video Definition 44--3D Geometry--Surface Area | Surface AreaTopic3D Geometry DefinitionSurface area is the total area covered by the surface of a three-dimensional object. |
Surface Area | |
Video Definition 44--3D Geometry--Surface Area--Spanish Audio | Video Definition 44--3D Geometry--Surface Area--Spanish Audio This is part of a collection of math video definitions related to the topic of 3D Geometry. These videos have Spanish audio. Note: The download is an MP4 video. |
Surface Area | |
Video Transcript: Geometry Applications: Area and Volume, Segment 2: Surface Area. | Video Transcript: Geometry Applications: Area and Volume, Segment 2: Surface Area.
This is the transcript for the video of same title. Video contents: The glass-paneled pyramid at the Louvre Museum in Paris is a tessellation of rhombus-shaped glass panels. Students create a model of the pyramid to calculate the number of panels used to cover the surface area of the pyramid. |
Applications of Surface Area and Volume | |
Video Transcript: Geometry Applications: Area and Volume, Segment 3: Ratio of Surface Area to Volume | Video Transcript: Geometry Applications: Area and Volume, Segment 3: Ratio of Surface Area to Volume
This is the transcript for the video of same title. Video contents: The Citibank Tower in New York City presents some unique design challenges. In addition it has to cope with a problem that all tall structure have to deal with: heat loss. By managing the ratio of surface area to volume, a skyscraper can effective manage heat loss. |
Applications of Surface Area and Volume |