Illustrative Math Alignment: Grade 7 Unit 9

Putting it All Together

Lesson 5: How Crowded Is this Neighborhood?

Use the following Media4Math resources with this Illustrative Math lesson.

Title	Body	Curriculum Topic
Math Example--Area and Perimeter--Quadrilaterals: Example 23	Math Example--Area and Perimeter--Quadrilaterals: Example 23 Topic Geometry Description This example demonstrates how to calculate the perimeter of a kite. The kite ABCD has two pairs of equal sides: AB and AD measure 22 units each, while BC and CD measure 11 units each. To find the perimeter, we add all four side lengths. In this case, P = 22 + 22 + 11 + 11 = 66 units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 24	Math Example--Area and Perimeter--Quadrilaterals: Example 24 Topic Geometry Description This example illustrates the calculation of a kite's perimeter using algebraic expressions. The kite ABCD has two pairs of equal sides: AB and AD measure x + 11 units each, while BC and CD measure x - 5 units each. To find the perimeter, we add all four side lengths. In this case, P = (x + 11) + (x + 11) + (x - 5) + (x - 5) = 4x + 12 units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 24	Math Example--Area and Perimeter--Quadrilaterals: Example 24 Topic Geometry Description This example illustrates the calculation of a kite's perimeter using algebraic expressions. The kite ABCD has two pairs of equal sides: AB and AD measure x + 11 units each, while BC and CD measure x - 5 units each. To find the perimeter, we add all four side lengths. In this case, P = (x + 11) + (x + 11) + (x - 5) + (x - 5) = 4x + 12 units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 24	Math Example--Area and Perimeter--Quadrilaterals: Example 24 Topic Geometry Description This example illustrates the calculation of a kite's perimeter using algebraic expressions. The kite ABCD has two pairs of equal sides: AB and AD measure x + 11 units each, while BC and CD measure x - 5 units each. To find the perimeter, we add all four side lengths. In this case, P = (x + 11) + (x + 11) + (x - 5) + (x - 5) = 4x + 12 units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 3	Math Example--Area and Perimeter--Quadrilaterals: Example 3 Topic Geometry Description This example demonstrates how to calculate the area of a rectangle. The rectangle ABCD has a length of 12 units and a width of 8 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = 12 × 8 = 96 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 3	Math Example--Area and Perimeter--Quadrilaterals: Example 3 Topic Geometry Description This example demonstrates how to calculate the area of a rectangle. The rectangle ABCD has a length of 12 units and a width of 8 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = 12 × 8 = 96 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 3	Math Example--Area and Perimeter--Quadrilaterals: Example 3 Topic Geometry Description This example demonstrates how to calculate the area of a rectangle. The rectangle ABCD has a length of 12 units and a width of 8 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = 12 × 8 = 96 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 4	Math Example--Area and Perimeter--Quadrilaterals: Example 4 Topic Geometry Description This example demonstrates the calculation of a rectangle's area using algebraic expressions. The rectangle ABCD has a length of x + 10 units and a width of x - 3 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = (x + 10)(x - 3) = x² + 7x - 30 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 4	Math Example--Area and Perimeter--Quadrilaterals: Example 4 Topic Geometry Description This example demonstrates the calculation of a rectangle's area using algebraic expressions. The rectangle ABCD has a length of x + 10 units and a width of x - 3 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = (x + 10)(x - 3) = x² + 7x - 30 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 4	Math Example--Area and Perimeter--Quadrilaterals: Example 4 Topic Geometry Description This example demonstrates the calculation of a rectangle's area using algebraic expressions. The rectangle ABCD has a length of x + 10 units and a width of x - 3 units. To find the area, we use the formula A = l × w, where l is the length and w is the width. In this case, A = (x + 10)(x - 3) = x² + 7x - 30 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 5	Math Example--Area and Perimeter--Quadrilaterals: Example 5 Topic Geometry Description This example illustrates how to calculate the area of a parallelogram. The parallelogram ABCD has a base of 15 units and a height of 7 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 15 × 7 = 105 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 5	Math Example--Area and Perimeter--Quadrilaterals: Example 5 Topic Geometry Description This example illustrates how to calculate the area of a parallelogram. The parallelogram ABCD has a base of 15 units and a height of 7 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 15 × 7 = 105 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 5	Math Example--Area and Perimeter--Quadrilaterals: Example 5 Topic Geometry Description This example illustrates how to calculate the area of a parallelogram. The parallelogram ABCD has a base of 15 units and a height of 7 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 15 × 7 = 105 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 6	Math Example--Area and Perimeter--Quadrilaterals: Example 6 Topic Geometry Description This example demonstrates the calculation of a parallelogram's area using algebraic expressions. The parallelogram ABCD has a base of x + 9 units and a height of x - 4 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 9)(x - 4) = x² + 5x - 36 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 6	Math Example--Area and Perimeter--Quadrilaterals: Example 6 Topic Geometry Description This example demonstrates the calculation of a parallelogram's area using algebraic expressions. The parallelogram ABCD has a base of x + 9 units and a height of x - 4 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 9)(x - 4) = x² + 5x - 36 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 6	Math Example--Area and Perimeter--Quadrilaterals: Example 6 Topic Geometry Description This example demonstrates the calculation of a parallelogram's area using algebraic expressions. The parallelogram ABCD has a base of x + 9 units and a height of x - 4 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 9)(x - 4) = x² + 5x - 36 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 7	Math Example--Area and Perimeter--Quadrilaterals: Example 7 Topic Geometry Description This example illustrates how to calculate the area of a trapezoid. The trapezoid ABCD has a base of 20 units and a height of 16 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 20 × 16 = 320 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 7	Math Example--Area and Perimeter--Quadrilaterals: Example 7 Topic Geometry Description This example illustrates how to calculate the area of a trapezoid. The trapezoid ABCD has a base of 20 units and a height of 16 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 20 × 16 = 320 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 7	Math Example--Area and Perimeter--Quadrilaterals: Example 7 Topic Geometry Description This example illustrates how to calculate the area of a trapezoid. The trapezoid ABCD has a base of 20 units and a height of 16 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = 20 × 16 = 320 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 8	Math Example--Area and Perimeter--Quadrilaterals: Example 8 Topic Geometry Description This example demonstrates the calculation of a trapezoid's area using algebraic expressions. The trapezoid ABCD has a base of x + 12 units and a height of x - 5 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 12)(x - 5) = x² + 7x - 60 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 8	Math Example--Area and Perimeter--Quadrilaterals: Example 8 Topic Geometry Description This example demonstrates the calculation of a trapezoid's area using algebraic expressions. The trapezoid ABCD has a base of x + 12 units and a height of x - 5 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 12)(x - 5) = x² + 7x - 60 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 8	Math Example--Area and Perimeter--Quadrilaterals: Example 8 Topic Geometry Description This example demonstrates the calculation of a trapezoid's area using algebraic expressions. The trapezoid ABCD has a base of x + 12 units and a height of x - 5 units. To find the area, we use the formula A = b × h, where b is the base and h is the height. In this case, A = (x + 12)(x - 5) = x² + 7x - 60 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 9	Math Example--Area and Perimeter--Quadrilaterals: Example 9 Topic Geometry Description This example illustrates how to calculate the area of a rhombus. The rhombus ABCD has a side length of 25 units and a height (perpendicular distance between parallel sides) of 19 units. To find the area, we use the formula A = b × h, where b is the base (which is the same as the side length in a rhombus) and h is the height. In this case, A = 25 × 19 = 475 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 9	Math Example--Area and Perimeter--Quadrilaterals: Example 9 Topic Geometry Description This example illustrates how to calculate the area of a rhombus. The rhombus ABCD has a side length of 25 units and a height (perpendicular distance between parallel sides) of 19 units. To find the area, we use the formula A = b × h, where b is the base (which is the same as the side length in a rhombus) and h is the height. In this case, A = 25 × 19 = 475 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Quadrilaterals: Example 9	Math Example--Area and Perimeter--Quadrilaterals: Example 9 Topic Geometry Description This example illustrates how to calculate the area of a rhombus. The rhombus ABCD has a side length of 25 units and a height (perpendicular distance between parallel sides) of 19 units. To find the area, we use the formula A = b × h, where b is the base (which is the same as the side length in a rhombus) and h is the height. In this case, A = 25 × 19 = 475 square units.	Area and Perimeter of Quadrilaterals
Math Example--Area and Perimeter--Surface Area: Example 1	Math Example--Area and Perimeter--Surface Area: Example 1 Topic Surface Area Description This example demonstrates the calculation of surface area for a rectangular prism. The prism has dimensions of 25, 15, and 12 units. The surface area is determined by summing the areas of all faces, which is represented by the formula SA = 2ab + 2bc + 2ac. For this specific prism, the calculation yields a surface area of 1710 square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 10	Math Example--Area and Perimeter--Surface Area: Example 10 Topic Surface Area Description This example presents a general formula for calculating the surface area of a cylinder with radius y and height x. The surface area consists of two circular ends and the rectangular region forming the curved surface. The formula used is SA = 2πr2 + 2πrh, which simplifies to SA = 2πy(x + y), where y is the radius and x is the height of the cylinder.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 11	Math Example--Area and Perimeter--Surface Area: Example 11 Topic Surface Area Description This example demonstrates the calculation of surface area for a hollow cylinder with an outer radius of 10 units, an inner radius of 9 units, and a height of 15 units. The surface area is determined by subtracting the area of the hollow region from the full cylinder's surface area. The formula used is SA = 2πr12 - 2πr22 + 2πr1h, where r1 is the outer radius and r2 is the inner radius. For this specific hollow cylinder, the calculation yields a surface area of 338π square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 12	Math Example--Area and Perimeter--Surface Area: Example 12 Topic Surface Area Description This example presents a general formula for calculating the surface area of a hollow cylinder with an outer radius y, an inner radius y - 1, and a height x. The surface area is determined by subtracting the hollow region's area from the full cylinder's surface area. The formula used is SA = 2πr12 - 2πr22 + 2πr1h, which simplifies to SA = 2π(2y + xy - 1), where r1 is the outer radius (y) and r2 is the inner radius (y - 1).	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 13	Math Example--Area and Perimeter--Surface Area: Example 13 Topic Surface Area Description This example demonstrates the calculation of surface area for a rectangular-based pyramid with dimensions 11, 9, and 15 units. The pyramid is depicted with its net unfolded, showing two triangular faces and a rectangular base. The surface area is calculated using the formula SA = b1 * h + b2 * h + l * w, where b1 and b2 are the bases of the triangular faces, h is the height of the triangular faces, and l and w are the length and width of the rectangular base. For this specific pyramid, the calculation yields a surface area of 399 square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 14	Math Example--Area and Perimeter--Surface Area: Example 14 Topic Surface Area Description This example presents a general formula for calculating the surface area of a rectangular-based pyramid with dimensions labeled as x, y, and z. The pyramid is depicted with its net unfolded into two triangular faces and one rectangular base. The surface area is calculated using the formula SA = b1 * h + b2 * h + l * w, which simplifies to SA = xz + yz + xy, where x and y are the dimensions of the rectangular base, and z is the height of the triangular faces.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 15	Math Example--Area and Perimeter--Surface Area: Example 15 Topic Surface Area	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 16	Math Example--Area and Perimeter--Surface Area: Example 16 Topic Surface Area Description This example presents a general formula for calculating the surface area of a truncated rectangular-based pyramid with dimensions labeled as x - 3, y - 3, z, x, and y. The virtual pyramid is shown with its net unfolded into four parallelogram regions and two rectangles. The surface area is calculated using the formula SA = 2yz + 2xz + xy + (x - 3)(y - 3), which simplifies to SA = (yz + xz + xy) - (x + y - 9).	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 17	Math Example--Area and Perimeter--Surface Area: Example 17 Topic Surface Area Description This example demonstrates the calculation of surface area for a sphere with a radius of 3 units. The surface area is calculated using the formula SA = 4πr2, where r is the radius of the sphere. For this specific sphere, the calculation yields a surface area of 36π square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 18	Math Example--Area and Perimeter--Surface Area: Example 18 Topic Surface Area Description This example presents a general formula for calculating the surface area of a sphere with an unknown radius labeled as "x". The surface area is calculated using the formula SA = 4πr2, which in this case becomes SA = 4πx2, where x is the radius of the sphere.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 19	Math Example--Area and Perimeter--Surface Area: Example 19 Topic Surface Area Description This example demonstrates the calculation of surface area for a cube with a side length of 7 units. The surface area is calculated using the formula SA = 6s2, where s is the length of one side of the cube. For this specific cube, the calculation yields a surface area of 294 square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 2	Math Example--Area and Perimeter--Surface Area: Example 2 Topic Surface Area Description This example introduces a general formula for calculating the surface area of a rectangular prism with dimensions x, y, and z. The surface area is computed using the formula SA = 2xy + 2xz + 2yz, which can be simplified to 2(xy + xz + yz). This generalized approach allows for easy application to prisms of various sizes. Surface area calculations are fundamental in mathematics, with applications ranging from manufacturing to environmental science. This collection of examples aids in teaching the topic by presenting both specific and general cases, helping students understand how to apply formulas flexibly to different scenarios.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 20	Math Example--Area and Perimeter--Surface Area: Example 20 Topic Surface Area Description This example presents a general formula for calculating the surface area of a cube with an unknown side length labeled as "x". The surface area is calculated using the formula SA = 6s2, which in this case becomes SA = 6x2, where x is the length of one side of the cube.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 21	Math Example--Area and Perimeter--Surface Area: Example 21 Topic Surface Area Description This example demonstrates the calculation of surface area for a hollow cube with an outer side length of 9 units and an inner hollow square side length of 7 units. The surface area is calculated using the formula SA = 6 * s12 - 2 * s22, where s1 is the outer side length and s2 is the inner side length. For this specific hollow cube, the calculation yields a surface area of 388 square units.	Surface Area
Math Example--Area and Perimeter--Surface Area: Example 22	Math Example--Area and Perimeter--Surface Area: Example 22 Topic Surface Area Description This example presents a general formula for calculating the surface area of a hollow cube with variable dimensions. The outer side length is labeled as "x" and the inner hollow side length as "x - 2". The surface area is calculated using the formula SA = 6 * s12 - 2 * s22, where s1 = x and s2 = x - 2. After expanding and simplifying, the result is SA = 4(x2 + 2x - 2) square units.	Surface Area

Illustrative Math Alignment: Grade 7 Unit 9

Putting it All Together

Lesson 5: How Crowded Is this Neighborhood?

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