Use the following Media4Math resources with this Illustrative Math lesson.
Thumbnail Image | Title | Body | Curriculum Topic |
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Math Example--Ratios and Rates--Example 4 | Math Example--Ratios and Rates--Example 4TopicRatios and Rates DescriptionThis example explores ratios using purple and red socks. The image shows a collection of socks, and students are asked to determine the ratio of purple socks to red socks. The solution reveals that there is 1 pair of purple socks and 4 pairs of red socks, resulting in a ratio of 1 : 4, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 4 | Math Example--Ratios and Rates--Example 4TopicRatios and Rates DescriptionThis example explores ratios using purple and red socks. The image shows a collection of socks, and students are asked to determine the ratio of purple socks to red socks. The solution reveals that there is 1 pair of purple socks and 4 pairs of red socks, resulting in a ratio of 1 : 4, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 4 | Math Example--Ratios and Rates--Example 4TopicRatios and Rates DescriptionThis example explores ratios using purple and red socks. The image shows a collection of socks, and students are asked to determine the ratio of purple socks to red socks. The solution reveals that there is 1 pair of purple socks and 4 pairs of red socks, resulting in a ratio of 1 : 4, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 5 | Math Example--Ratios and Rates--Example 5TopicRatios and Rates DescriptionThis example focuses on ratios using black and green socks among a variety of colored socks. The image displays pairs of socks in black, green, orange, yellow, blue, and red. Students are asked to determine the ratio of black socks to green socks. The solution shows that there are 2 pairs of black socks and 10 pairs of green socks, resulting in a ratio of 2 : 10, which simplifies to 1 : 5. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 6 | Math Example--Ratios and Rates--Example 6TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes of different colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of circular shapes to yellow objects. The solution reveals that there are 2 circular shapes and 1 yellow object, resulting in a ratio of 2 : 1, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 7 | Math Example--Ratios and Rates--Example 7TopicRatios and Rates DescriptionThis example focuses on ratios using geometric shapes. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of triangles to quadrilaterals. The solution shows that there are 4 triangles and 6 quadrilaterals, resulting in a ratio of 4 : 6, which simplifies to 2 : 3. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 8 | Math Example--Ratios and Rates--Example 8TopicRatios and Rates DescriptionThis example explores ratios using geometric shapes and colors. The image displays various shapes in yellow, blue, red, and green. Students are asked to determine the ratio of octagons to blue shapes. The solution reveals that there are 2 octagons and 5 blue shapes, resulting in a ratio of 2 : 5, which is already in its simplest form. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios and Rates--Example 9 | Math Example--Ratios and Rates--Example 9TopicRatios and Rates DescriptionThis example introduces the concept of ratios in genetics using a Punnett square. The image shows genetic combinations for a flower's color, including RR, Rw, and ww, with corresponding images of red and white flowers. Students are asked to determine the ratio of different gene combinations. |
Ratios and Rates | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 1 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 1TopicRatios, Proportions, and Percents DescriptionThis example demonstrates how to solve a proportion problem where two ratios a:b and c:d are proportional. Given the values b = 3, c = 4, and d = 6, we need to find the value of a. The proportion is set up as a / 3 = 4 / 6, which is then solved to find that a = 2. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 1 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 1TopicRatios, Proportions, and Percents DescriptionThis example demonstrates how to solve a proportion problem where two ratios a:b and c:d are proportional. Given the values b = 3, c = 4, and d = 6, we need to find the value of a. The proportion is set up as a / 3 = 4 / 6, which is then solved to find that a = 2. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 10 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 10TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar triangles with algebraic expressions. Two triangles are shown, one with sides of 6 and 9, and the other with sides of 2x and 2x + 9. The problem requires setting up a proportion: 6 / 9 = 2x / (2x + 9). Solving this equation leads to x = 9, which then allows us to find the side lengths of 18 and 27. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 10 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 10TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar triangles with algebraic expressions. Two triangles are shown, one with sides of 6 and 9, and the other with sides of 2x and 2x + 9. The problem requires setting up a proportion: 6 / 9 = 2x / (2x + 9). Solving this equation leads to x = 9, which then allows us to find the side lengths of 18 and 27. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 11 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 11TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles. Two right triangles are shown, one with legs of 7 and 9, and the other with legs of 14 and x. The problem requires finding the length of side x by setting up a proportion based on the similar triangles: 7 / 9 = 14 / x. Solving this equation leads to x = 18. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 11 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 11TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles. Two right triangles are shown, one with legs of 7 and 9, and the other with legs of 14 and x. The problem requires finding the length of side x by setting up a proportion based on the similar triangles: 7 / 9 = 14 / x. Solving this equation leads to x = 18. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 12 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 12TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with algebraic expressions. Two right triangles are shown, one with legs of 5 and 8, and the other with legs of 2x and (2x + 6). The problem requires setting up a proportion: 5 / 8 = 2x / (2x + 6). Solving this equation leads to x = 5, which then allows us to find the side lengths of 10 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 12 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 12TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with algebraic expressions. Two right triangles are shown, one with legs of 5 and 8, and the other with legs of 2x and (2x + 6). The problem requires setting up a proportion: 5 / 8 = 2x / (2x + 6). Solving this equation leads to x = 5, which then allows us to find the side lengths of 10 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 13 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 13TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles with special angles (30°-60°-90°). Two triangles are shown, with the smaller one having sides of 6√3 and 6, and the larger one having sides of x and 12. The problem requires finding the length of side x by setting up a proportion: (6√3) / 6 = x / 12. Solving this equation leads to x = 12√3. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 13 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 13TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles with special angles (30°-60°-90°). Two triangles are shown, with the smaller one having sides of 6√3 and 6, and the larger one having sides of x and 12. The problem requires finding the length of side x by setting up a proportion: (6√3) / 6 = x / 12. Solving this equation leads to x = 12√3. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 14 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 14TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with special angles (30°-60°-90°) and algebraic expressions. Two triangles are shown, with the smaller one having sides of 16 and 8, and the larger one having sides of (3x + 4) and 2x. The problem requires setting up a proportion: 16 / 8 = (3x + 4) / 2x. Solving this equation leads to x = 4, which then allows us to find the side lengths of 8 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 14 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 14TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with special angles (30°-60°-90°) and algebraic expressions. Two triangles are shown, with the smaller one having sides of 16 and 8, and the larger one having sides of (3x + 4) and 2x. The problem requires setting up a proportion: 16 / 8 = (3x + 4) / 2x. Solving this equation leads to x = 4, which then allows us to find the side lengths of 8 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 15 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 15TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles. Two right triangles are shown, with the smaller one having sides of 4 and 3, and the larger one having sides of x and 12. The problem requires finding the length of side x by setting up a proportion: 4 / 3 = x / 12. Solving this equation leads to x = 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 15 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 15TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles. Two right triangles are shown, with the smaller one having sides of 4 and 3, and the larger one having sides of x and 12. The problem requires finding the length of side x by setting up a proportion: 4 / 3 = x / 12. Solving this equation leads to x = 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 16 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 16TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with algebraic expressions. Two right triangles are shown, with the smaller one having sides of (3x + 4) and 6, and the larger one having sides of 3x and 3x. The problem requires setting up a proportion: 8 / 6 = (3x + 4) / 3x. Solving this equation leads to x = 4, which then allows us to find the side lengths of 12 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 16 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 16TopicRatios, Proportions, and Percents DescriptionThis example illustrates solving a proportion problem using similar right triangles with algebraic expressions. Two right triangles are shown, with the smaller one having sides of (3x + 4) and 6, and the larger one having sides of 3x and 3x. The problem requires setting up a proportion: 8 / 6 = (3x + 4) / 3x. Solving this equation leads to x = 4, which then allows us to find the side lengths of 12 and 16. |
Proportions | |
Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 17 | Math Example--Ratios, Proportions, and Percents--Solving Proportions: Example 17TopicRatios, Proportions, and Percents DescriptionThis example demonstrates solving a proportion problem using similar right triangles. Two right triangles are shown, with the left one having sides of 12 and 5, and the right one having sides of x and 15. The problem requires finding the length of side x by setting up a proportion: 12 / 5 = x / 15. Solving this equation leads to x = 36. |
Proportions |