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Illustrative Math-Media4Math Alignment

 

 

Illustrative Math Alignment: Grade 8 Unit 3

Linear Relationships

Lesson 6: More Linear Relationships

Use the following Media4Math resources with this Illustrative Math lesson.

Thumbnail Image Title Body Curriculum Topic
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 2 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 2 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 2

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation 3x + 6y = -18 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = -1/2 x - 3. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 20

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -14x - 35y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = -2/5 x. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 21

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 28x - 21y = 0 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 4/3 x. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 22

Topic

Linear Functions

Description

This example illustrates the conversion of the linear equation -13x + 39y = 0 from standard form to slope-intercept form. The solution involves isolating y and dividing by its coefficient, resulting in y = 1/3 x. This process clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 3

Topic

Linear Functions

Description

This example showcases the transformation of the linear equation 5x - 2y = 12 from standard form to slope-intercept form. The process involves isolating y and dividing by its coefficient, resulting in y = 2.5x - 6. This step-by-step solution clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 4

Topic

Linear Functions

Description

This example demonstrates the conversion of the linear equation -6x + 10y = 20 from standard form to slope-intercept form. The solution process involves isolating y and dividing by its coefficient, resulting in y = 0.6x + 2. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form
Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5 Math Example--Linear Function Concepts--Linear Equations in Standard Form: Example 5

Topic

Linear Functions

Description

This example illustrates the process of converting the linear equation -9x - 15y = -45 from standard form to slope-intercept form. The solution involves rearranging the equation to isolate y, resulting in y = 3/5 x + 3. This transformation clearly reveals the slope and y-intercept of the line.

Standard Form