Use the following Media4Math resources with this Illustrative Math lesson.
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: Graphs of Absolute Value Functions | In this Slide Show, absolute value functions are graphed, including graphs centered at the origin, graphs displaced along the x-axis, and graphs displaced along the y-axis. This presentation requires the use of the TI-Nspire iPad App. Note: the download is a PPT. |
Special Functions |
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: Graphs of Inequalities | In this Slide Show, the Graph Window is used to graph linear inequalities. This presentation requires the use of the TI-Nspire iPad App. Note: the download is a PPT. |
Inequalities and Applications of Linear Functions |
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: Graphs of Inequalities with Sliders | In this Slide Show, the Graph Window is used to graph inequalities using sliders. This presentation requires the use of the TI-Nspire iPad App. Note: the download is a PPT. |
Inequalities and Applications of Linear Functions |
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: Graphs of Linear Functions | In this Slide Show, linear functions are graphed. This presentation requires the use of the TI-Nspire iPad App. Note: the download is a PPT. |
Applications of Linear Functions |
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: Parallel and Perpendicular Lines | In this Slide Show, explore the properties of parallel and perpendicular lines. Use a slider to define the slope and then graph parallel and perpendicular lines linked to this slider. |
Parallel Lines and Perpendicular Lines |
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INSTRUCTIONAL RESOURCE: Nspire App Tutorial: The Perpendicular Bisectors of a Triangle | In this Slide Show, we show how to construct the perpendicular bisectors of the three sides of a triangle to show they intersect at a single point. This presentation requires the use of the TI-Nspire iPad App. Note: the download is a PPT. |
Definition of a Triangle and Geometric Constructions with Triangles |
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Instructional Resource: TI-Nspire Activity: Exploring the Ratio of Circumference to Radius as a Linear Function | In this TI-Nspire Activity, use the Geometry and Graphing Tools to explore the ratio of Circumference to Radius as a linear function. Note: The Preview is a Google Slide Show and the download is a PPT. Subscribers to Media4Math can download resources. To see the complete collection of TI graphing calculator resources, click on this Link. |
Applications of Linear Functions, Applications of Circles and Geometric Constructions with Circles |
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Interactive Crossword Puzzle--Parallel and Perpendicular Lines | Interactive Crossword Puzzle--Parallel and Perpendicular Lines
This interactive crossword puzzle tests knowledge of key terms on the topic of the graphs of Parallel and Perpendicular Lines. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Parallel Lines and Perpendicular Lines |
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Interactive Math Game--Algebra Jeopardy: Linear Functions | Interactive Math Game--Algebra Jeopardy: Linear Functions
Use this Jeopardy-style math game to review linear functions. This Jeopardy game has a bank of hundreds of questions for thousands of unique game experiences. To see the complete set of Math Games and Puzzles, click on this link. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Graphs of Linear Functions and Slope-Intercept Form |
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Interactive Math Game--DragNDrop--Equations of Parallel Lines | Interactive Math Game--DragNDrop Math--Equations of Parallel Lines
In this drag-and-drop game, match the linear equation with the equation of a parallel line through a given point. This game generates thousands of different equation combinations, offering an ideal opportunity for skill review in a game format. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Slope and Slope-Intercept Form |
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Interactive Math Game--DragNDrop--Equations of Perpendicular Lines | Interactive Math Game--DragNDrop Math--Equations of Perpendicular Lines
In this drag-and-drop game, match the linear equation with the equation of a perpendicular line through a given point. This game generates thousands of different equation combinations, offering an ideal opportunity for skill review in a game format. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Slope and Slope-Intercept Form |
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Interactive Math Game--DragNDrop--Evaluating Linear Functions | Interactive Math Game--DragNDrop Math--Evaluating Linear Functions
In this drag-and-drop game, match f(x) with f(a) for a given value of a. This game generates thousands of different equation combinations, offering an ideal opportunity for skill review in a game format. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Applications of Linear Functions |
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Interactive Math Game--Equation Burst: Linear Functions | Interactive Math Game--Equation Burst: Linear Functions
Use this math game to review linear functions in slope-intercept form. This is part of a collection of math games and interactives. To see the complete collection of the games, click on this link. Note: The download is the teacher's guide.Related ResourcesTo see additional resources on this topic, click on the Related Resources tab. |
Slope-Intercept Form |
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Lesson Plan--Ratios, Proportions, and Percents (Gr 8)--Lesson 4--Understanding Direct Variation and Its Connection to Proportional Relationships | Lesson Plan: Direct Variations In this lesson, students will explore direct variation, a special type of proportional relationship where one variable is a constant multiple of another. They will learn how to identify direct variation in tables, graphs, and equations, determine the constant of variation (k), and understand how direct variation relates to linear functions. Key concepts covered in this lesson include: |
Applications of Linear Functions and Applications of Ratios, Proportions, and Percents |
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Lesson Plan--Ratios, Proportions, and Percents (Gr 8)--Lesson 5--Analyzing and Comparing Linear Relationships, Including Parallel and Perpendicular Lines | Lesson Plan: Parallel and Perpendicular Lines In this lesson, students explore the properties of parallel and perpendicular lines in coordinate geometry. They will learn how to identify these lines based on their slopes, determine equations for parallel and perpendicular lines, and apply these concepts to solve real-world and mathematical problems. Key concepts covered in this lesson include: |
Graphs of Linear Functions |
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Lesson Plan--Slope Concepts--Lesson 3--Visualizing Slope | Lesson Plan: Visualizing Slope on a Graph This lesson is the third installment in Media4Math's comprehensive six-part series on understanding slope in mathematics. It focuses on helping students visualize and comprehend slope by engaging in hands-on activities that involve plotting points on a coordinate plane and analyzing the resulting lines. |
Slope |
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Lesson Plan--Slope Concepts--Lesson 6--Slope as Rate of Change | Lesson Plan: Slope as Rate of Change This lesson is the sixth and final installment in Media4Math's comprehensive six-part series on understanding slope in mathematics. It focuses on interpreting slope as a rate of change between two quantities, enabling students to apply this concept to real-world scenarios and mathematical problems. |
Slope |
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Lesson Plan: Cross-Sections of 3D Figures, Part 1 | Lesson Plan: Cross-Sections of 3D Figures In this engaging math lesson, students explore cross-sections of cubes, cylinders, and cones through interactive activities, real-world examples, and animated visuals. They will learn how slicing three-dimensional shapes in different ways produces a variety of two-dimensional figures, helping to develop spatial reasoning and geometric understanding. The lesson begins with a conceptual introduction to cross-sections, followed by hands-on practice with everyday objects such as gift boxes, paper towel rolls, and ice cream cones. Students will investigate how horizontal, vertical, and diagonal slices impact the resulting shapes. Animated GIFs illustrate these concepts, reinforcing learning through dynamic visual representations. |
3-Dimensional Figures |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 1 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 1TopicPolynomials DescriptionAn example showing how to find the side lengths of a square given its area, A = x2+ 2x + 1. Example 1: Given the area A = x2+ 2x + 1, find the side lengths. Solution: Express the area as a perfect square, (x + 1)2, so the side lengths are x + 1. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 2 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 2TopicPolynomials DescriptionAnother example of finding the side lengths of a square with area A = x2+ 4x + 4. Example 2: Given A = x2+ 4x + 4, find the side lengths. Solution: Factor as (x + 2)2, so the side lengths are x + 2. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 3 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 3TopicPolynomials DescriptionShows how to determine the side lengths of a square with area A = x2 - 2x + 1. Example 3: For A = x2 - 2x + 1, the solution expresses it as (x - 1)2, making the side lengths x - 1. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 4 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 4TopicPolynomials DescriptionExample solving for side lengths of a square with area A = x2 - 4x + 4. Example 4: Given A = x2 - 4x + 4, factor as (x - 2)2 to find side lengths x - 2. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 5 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 5TopicPolynomials DescriptionSolves for side lengths of a square with area A = x2 + 6x + 9. Example 5: With A = x2 + 6x + 9, factor as (x + 3)2, giving side lengths x + 3. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 6 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 6TopicPolynomials DescriptionA cubic example where the volume of a cube, A = x3 + 3x2 + 3x + 1, is used to find the side length. Example 6: Given the volume A = x3 + 3x2 + 3x + 1, factor as (x + 1)3, so the side lengths are x + 1. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 7 | Math Example--Polynomial Concepts-- Perfect Squares and Cubes--Example 7TopicPolynomials DescriptionAnother cubic example solving for side length with volume A = x3 - 3x2 + 3x - 1. Example 7: For the volume A = x3 - 3x2 + 3x - 1, express as (x - 1)3 to determine side lengths of x - 1. Polynomials involve expressions with variables raised to powers, and these examples specifically address perfect squares and cubes. Each example in this collection explores how to derive side lengths or volumes using factorization, demonstrating the practical applications of polynomial expressions. |
Variable Expressions |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 1 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 1
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 10 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 10
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 2 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 2
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 3 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 3
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 4 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 4
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 5 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 5
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 6 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 6
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 7 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 7
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 8 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 8
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Mass and Volume--Example 9 | Math Example--Volume Concepts--Calculating Mass and Volume--Example 9
This is part of a collection of math examples that focus on volume. |
Mass and Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 1 | Math Example--Volume Concepts--Calculating Volume: Example 1TopicVolume DescriptionA rectangular prism with dimensions labeled: length = 30, width = 10, and height = 8. The image shows how to find the volume of the prism using the formula for volume of a rectangular prism. This image illustrates Example 1: The caption explains how to calculate the volume of the rectangular prism using the formula V = l * w * h. The given dimensions are substituted into the formula: V = 30 * 10 * 8 = 2400.. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 10 | Math Example--Volume Concepts--Calculating Volume: Example 10TopicVolume DescriptionA green cylinder with a general radius y and height x. The radius is marked on the top surface, and the height is marked on the side. This image illustrates Example 10: The task is to find the volume of this cylinder. The volume formula V = πr2h is used, and substituting r = y and h = x, the volume is calculated as V = xy2π. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 11 | Math Example--Volume Concepts--Calculating Volume: Example 11TopicVolume DescriptionA hollow green cylinder with an outer radius of 10 units, an inner radius of 9 units, and a height of 15 units. The radii are marked on the top surface, and the height is marked on the side. This image illustrates Example 11: The task is to find the volume of this hollow cylinder. The volume formula for a hollow cylinder V = πr12h1 - πr22h2 is used. Substituting values, the result is V = 285π. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 12 | Math Example--Volume Concepts--Calculating Volume: Example 12TopicVolume DescriptionA hollow green cylinder with an outer radius y, an inner radius y - 1, and a height x. The radii are marked on the top surface, and the height is marked on the side. This image illustrates Example 12: The task is to find the volume of this hollow cylinder. Using V = π(r12h1 - r22h2), substituting values gives: V = πx(y2 - (y - 1)2= πx(2y - 1). |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 13 | Math Example--Volume Concepts--Calculating Volume: Example 13TopicVolume DescriptionA rectangular-based pyramid is shown with dimensions: base length 10, base width 8, and height 30. The image demonstrates how to calculate the volume of this pyramid. This image illustrates Example 13: The caption provides a step-by-step solution for calculating the volume of a pyramid with a rectangular base using the formula V = (1/3) * Area of Base * h. Substituting values: V = (1/3) * 8 * 10 * 30 = 800. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 14 | Math Example--Volume Concepts--Calculating Volume: Example 14TopicVolume DescriptionA general rectangular-based pyramid is shown with variables x, y, and z representing the base dimensions and height. This example shows how to calculate the volume of a pyramid using variables instead of specific numbers. This image illustrates Example 14: The caption explains how to calculate the volume of a pyramid with a rectangular base using the formula V = (1/3) * Area of Base * h, which simplifies to V = (1/3) * x * y * z. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 15 | Math Example--Volume Concepts--Calculating Volume: Example 15TopicVolume |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 16 | Math Example--Volume Concepts--Calculating Volume: Example 16TopicVolume DescriptionA truncated rectangular-based pyramid is shown with variables x, y, and z representing dimensions. The smaller virtual pyramid has reduced dimensions by 3 units for both width and length and reduced height by z - 20. The image demonstrates how to calculate the volume in terms of variables. This image illustrates Example 16: The caption explains how to find the volume of a truncated pyramid using variables for both pyramids' dimensions. Formula: V = (1/3) * xy(z + 20) - (1/3) * (y - 3)(x - 3)(z), which simplifies to V = (1/3) * (xyz + 60x + 60y - 180). |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 17 | Math Example--Volume Concepts--Calculating Volume: Example 17TopicVolume DescriptionA green sphere with a radius labeled as 3. The image is part of a math example showing how to calculate the volume of a sphere. This image illustrates Example 17: The text describes finding the volume of a sphere. The formula used is V = (4/3) * π * r3, where r = 3. After substituting, the result is V = 36π. Volume is a fundamental concept in geometry that helps students understand the space occupied by three-dimensional objects. In this collection, each example uses various geometric shapes to calculate volume, showcasing real-life applications of volume in different shapes. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 18 | Math Example--Volume Concepts--Calculating Volume: Example 18TopicVolume Description
A green sphere with a radius labeled as x. This image is part of a math example showing how to calculate the volume of a sphere using an unknown radius. This image illustrates Example 18: The text explains how to find the volume of a sphere with an unknown radius x. The formula used is V = (4/3) * π * r3, and substituting r = x gives V = (4/3) * x3 * π. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 19 | Math Example--Volume Concepts--Calculating Volume: Example 19TopicVolume Description
A green cube with side length labeled as 7. The image illustrates how to calculate the volume of a cube with known side length. This image illustrates Example 19: The text describes finding the volume of a cube. The formula used is V = s3, where s = 7. After substituting, the result is V = 343. Volume is a fundamental concept in geometry that helps students understand the space occupied by three-dimensional objects. In this collection, each example uses various geometric shapes to calculate volume, showcasing real-life applications of volume in different shapes. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 2 | Math Example--Volume Concepts--Calculating Volume: Example 2TopicVolume DescriptionA rectangular prism with dimensions labeled as x, y, and z. The image shows a general example of calculating the volume of a rectangular prism using variables instead of specific numbers. This image illustrates Example 2: The caption describes how to find the volume of a rectangular prism using variables for length (x), width (y), and height (z). The formula is given as V = x * y * z, but no specific values are provided. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 20 | Math Example--Volume Concepts--Calculating Volume: Example 20TopicVolume DescriptionA green cube with side length labeled as x. This image is part of a math example showing how to calculate the volume of a cube using an unknown side length. This image illustrates Example 20: The text explains how to find the volume of a cube with an unknown side length x. The formula used is V = s3, and substituting s = x gives V = x3. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 21 | Math Example--Volume Concepts--Calculating Volume: Example 21TopicVolume DescriptionA hollow cube with an outer edge of 9 and an inner hollow region with an edge of 7. The image shows how to calculate the volume by subtracting the volume of the inner cube from the outer cube. This image illustrates Example 21: Find the volume of a hollow cube. The formula used is V = s13 - s23, where s1 is the outer edge (9) and s2 is the inner edge (7). The solution calculates 9^3 - 7^3 = 386.. |
Volume |
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Math Example--Volume Concepts--Calculating Volume: Example 22 | Math Example--Volume Concepts--Calculating Volume: Example 22TopicVolume DescriptionA hollow cube with an outer edge of x and an inner hollow region with an edge of x - 2. The image shows how to calculate the volume by subtracting the volume of the inner cube from the outer cube. This image illustrates Example 22: Find the volume of a hollow cube. The formula used is V = s13 - s23, where s1 = x and s2 = x - 2. Expanding and simplifying gives V = 6x2 - 12x + 8. |
Volume |