Illustrative Math Alignment: Grade 8 Unit 3
Linear Relationships
Lesson 5: Introduction to Linear Relationships
Use the following Media4Math resources with this Illustrative Math lesson.
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 4 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 4TopicLinear Functions DescriptionThis example illustrates how to find the equation of a vertical line passing through the points (5, 3) and (5, 8). The slope is undefined because both x-coordinates are the same, resulting in division by zero when using the slope formula. This indicates a vertical line, and the equation is simply x = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 5TopicLinear Functions DescriptionThis example demonstrates how to find the equation of a line passing through the points (-6, 1) and (-2, 3). The slope is calculated using the formula (y2 - y1) / (x2 - x1), resulting in a slope of 1/2. Using the point-slope form of a line, y - y1 = m(x - x1), the equation is derived and simplified to y = (1/2)x + 4. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 6TopicLinear Functions DescriptionThis image shows a graph with two points (-8, 4) and (-4, 2). The slope is calculated as (y2 - y1) / (x2 - x1), resulting in a slope of -1/2. The equation of the line is derived using point-slope form and simplified to y = -(1/2)x. The slope is calculated as -1/2, and the line equation is determined using point-slope form: y = -(1/2)x. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 7TopicLinear Functions DescriptionThis image shows a graph with two points (-7, 5) and (-1, 5). The slope is calculated as zero since the y-values are equal. The equation of the line is horizontal, simplified to y = 5. The slope is 0, indicating a horizontal line. The equation is y = 5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 8TopicLinear Functions DescriptionThis image shows a graph with two points (-5, 6) and (-5, 3). The slope is undefined because the x-values are equal. This results in a vertical line at x = -5. The slope is undefined, indicating a vertical line at x = -5. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9 | Math Example--Linear Function Concepts--The Equation of a Line Given Two Points: Example 9TopicLinear Functions DescriptionThe image shows a coordinate plane with two points (-5, -4) and (-4, -1) marked. It provides a step-by-step solution to find the equation of the line passing through these points. The slope is calculated, and the equation is derived using point-slope form. The slope is calculated as (y2 - y1) / (x2 - x1) = (-1 - (-4)) / (-4 - (-5)) = 3 / 1 = 3. Using point-slope form, y - y1 = m(x - x1), the equation is derived as y + 1 = 3(x + 4), which simplifies to y = 3x + 11. |
Point-Slope Form and Slope-Intercept Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 1TopicThe Point-Slope Form DescriptionThis example demonstrates how to find the equation of a line using the point-slope form. The given information includes a slope of 5 and a point (6, 5) through which the line passes. Using the point-slope formula y - y1 = m(x - x1), we can substitute the known values to derive the equation y - 5 = 5(x - 6). Simplifying this equation leads to the final result: y = 5x - 25. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 2TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -1 passing through the point (5, 2). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 2 = -(x - 5). After simplification, the final equation of the line is y = -x + 7. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 3TopicThe Point-Slope Form DescriptionThis example demonstrates the application of the point-slope formula to find the equation of a line with a slope of 3 passing through the point (-2, 7). Using the formula y - y1 = m(x - x1), we substitute the given values to get y - 7 = 3(x - (-2)). After simplification, the resulting equation is y = 3x + 13. |
Point-Slope Form |
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Math Example--Linear Function Concepts--The Point-Slope Formula: Example 4 | Math Example--Linear Function Concepts--The Point-Slope Formula: Example 4TopicThe Point-Slope Form DescriptionIn this example, we explore finding the equation of a line with a slope of -5 that passes through the point (-7, 5). Applying the point-slope formula y - y1 = m(x - x1), we substitute the given values to obtain y - 5 = -5(x - (-7)). After simplification, the final equation of the line is y = -5x - 30. |
Point-Slope Form |
