Use the following Media4Math resources with this Illustrative Math lesson.
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Math Example--Area and Perimeter--Circular Area and Circumference: Example 14 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 14TopicGeometry DescriptionThis example features a circle with radius x and a shaded sector with a central angle of 30 degrees. The task is to express the area of the shaded sector in terms of x. The solution involves using the central angle to find the fractional amount of the total area: Area = (30 / 360) * (π * x2) = π * x2 / 12. |
Area and Circumference | |
Definition--Geometry Basics--Circumference | CircumferenceTopicGeometry Basics DefinitionThe distance around the edge of a circle. DescriptionThe circumference is the distance around the edge of a circle. This concept is fundamental in understanding the properties of circles and their measurements. The formula for the circumference is C = 2πr, where r is the radius of the circle. Understanding the circumference is crucial for solving problems related to circle geometry, such as finding the length of an arc or the area of a sector. |
Definition of a Circle | |
INSTRUCTIONAL RESOURCE: Algebra Application: Linear Functions: Circumference vs. Diameter | INSTRUCTIONAL RESOURCE: Algebra Application: Linear Functions: Circumference vs. Diameter
In this Algebra Application, students study the direction between diameter and circumference of a circle. Through measurement and data gathering students analyze the line of best fit and explore ways of calculating pi. The math topics covered include: Mathematical modeling, Linear functions, Data gathering and analysis, Ratios, Direct variation. This is a great back-to-school activity for middle school or high school students. This is also a great crossover activity that ties algebra and geometry. |
Applications of Linear Functions, Applications of Ratios, Proportions, and Percents and Applications of Circles | |
Definition--Circle Concepts--Circumference | CircumferenceTopicCircles DefinitionThe circumference of a circle is the distance around the circle, calculated as C = 2πr. DescriptionThe circumference is a fundamental concept in geometry, representing the perimeter of a circle. It is widely used in fields such as engineering, design, and manufacturing, where precise measurements of circular objects are required. The formula C = 2πr |
Definition of a Circle | |
Definition--Circle Concepts--Ratio of Circumference to Diameter | Ratio of Circumference to DiameterTopicCircles DefinitionThe ratio of the circumference to the diameter of a circle is the constant π. |
Definition of a Circle | |
Instructional Resource: TI-Nspire Activity: Exploring the Ratio of Circumference to Radius as a Linear Function | In this TI-Nspire Activity, use the Geometry and Graphing Tools to explore the ratio of Circumference to Radius as a linear function. Note: The Preview is a Google Slide Show and the download is a PPT. Subscribers to Media4Math can download resources. To see the complete collection of TI graphing calculator resources, click on this Link. |
Applications of Linear Functions, Applications of Circles and Geometric Constructions with Circles | |
MATH EXAMPLES--Teacher's Guide: Circular Area and Circumference | MATH EXAMPLES--Teacher's Guide: Circular Area and Circumference
This set of tutorials provides 23 examples of solving for the area and circumferences of circles and sections of circles. This is part of a collection of teacher's guides. To see the complete collection of teacher's guides, click on this link. Note: The download is a PDF file.Related ResourcesTo see resources related to this topic click on the Related Resources tab above. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 23 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 23TopicGeometry DescriptionThis example features two concentric circles with radii x and 4, and a shaded sector with a central angle θ (theta). The task is to express the perimeter of the shaded region in terms of x and θ. The solution involves calculating arc lengths based on the central angle and adding straight-line segments between radii: Perimeter = (θ / 360) * (2 * π * x + 2 * π * 4) + 2 * (x - 4) = (π / 180) * θ(x + 4) + 2(x - 4). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 22 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 22TopicGeometry DescriptionThis example presents two concentric circles with radii 4 and x, and a shaded sector with a central angle θ (theta). The task is to express the area of the shaded region in terms of x and θ. The solution uses the central angle to find the fractional area difference between the larger and smaller circles: Area = (θ / 360) * (π * x2 - π * 42) = (θ * π / 360) * (x2 - 16). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 21 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 21TopicGeometry DescriptionThis example features two concentric circles with radii 5 and y, and a shaded sector with a central angle of 30 degrees. The task is to calculate the perimeter of the shaded region. Given a central angle of 30 degrees, radius 5, and unknown radius y, the perimeter is calculated as: Perimeter = π/6 * (5 + y) + 2(5 - y). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 20 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 20TopicGeometry DescriptionThis example features two concentric circles with radii 5 and y, and a shaded sector with a central angle of 30 degrees. The task is to express the area of the shaded region in terms of y. The solution involves calculating the difference between the areas of the larger and smaller circles, accounting for the central angle: Area = π/12 * (25 - y2). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 19 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 19TopicGeometry DescriptionThis example presents two concentric circles with radii x and y, and a shaded sector with a central angle θ (theta). The task is to express the perimeter of the shaded region in terms of x, y, and θ. The solution involves calculating arc lengths based on the central angle and adding straight-line segments between radii: Perimeter = (θ / 360) * (2πx + 2πy) + 2(x - y) = π/180 * θ(x + y) + 2(x - y). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 18 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 18TopicGeometry DescriptionThis example features two concentric circles with radii x and y, and a shaded sector with a central angle θ (theta). The task is to express the area of the shaded region in terms of x, y, and θ. The solution uses the central angle to find the fractional area difference between the larger and smaller circles: Area = (θ / 360) * (π * x2 - π * y2) = (θπ / 360) * (x2 - y2). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 17 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 17TopicGeometry DescriptionThis example presents two concentric circles with radii of 5 and 4 units, and a shaded sector with a central angle of 30 degrees. The task is to calculate the perimeter of the shaded region. The solution involves calculating arc lengths based on the central angle and adding straight-line segments between radii: Perimeter = (θ / 360) * (2 * π * r1 + 2 * π * r2) + 2 * (r1 - r2) = (30 / 360) * (2π * 5 + 2π * 4) + 2 * (5 - 4) = 3π / 2 + 2. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 16 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 16TopicGeometry DescriptionThis example features two concentric circles with radii of 5 and 4 units, and a shaded sector with a central angle of 30 degrees. The task is to calculate the area of the shaded region. The solution involves using the central angle to determine the fractional area difference between the larger and smaller circles: Area = (θ / 360) * (π * r12 - π * r22) = (30 / 360) * (π * 52 - π * 42) = π / 12 * (25 - 16) = 3π / 4. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 15 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 15TopicGeometry DescriptionThis example presents a circle with radius x and a shaded sector with a central angle of 30 degrees. The task is to express the arc length of the shaded region in terms of x. The solution involves using the central angle to find the fractional amount of the circumference: Arc Length = (30 / 360) * (2 * π * x) = x / 6 * π. |
Area and Circumference | |
Instructional Resource: Applications of Linear Functions: Circumference vs. Diameter | In this Slide Show, apply concepts of linear functions to the context of circumference vs. diameter. Note: The download is a PPT file. Related ResourcesTo see the complete collection of Tutorials on this topic, click on this link: https://bit.ly/3g0P3cN |
Applications of Linear Functions | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 13 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 13TopicGeometry DescriptionThis example presents a circle with a radius of 5 units and a shaded sector with central angle θ (theta). The task is to express the arc length of the shaded region in terms of θ. The solution involves using the central angle to find the fractional amount of the circumference: Arc Length = (θ / 360) * (2 * π * 5) = θ / 18 * π. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 12 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 12TopicGeometry DescriptionThis example features a circle with a radius of 5 units and a shaded sector with central angle θ (theta). The task is to express the area of the shaded sector in terms of θ. The solution involves using the central angle to find the fractional amount of the total area: Area = (θ / 360) * (π * 52) = 25π / 360 * θ = 5π / 72 * θ. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 11 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 11TopicGeometry DescriptionThis example presents a circle with radius x and a shaded sector with central angle θ (theta). The task is to express the arc length of the shaded region in terms of x and θ. The solution involves using the central angle to find the fractional amount of the circumference: Arc Length = (θ / 360) * (2 * π * x) = (θ * x / 180) * π. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 10 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 10TopicGeometry DescriptionThis example presents a circle with radius x and a shaded sector with central angle θ (theta). The task is to express the area of the shaded sector in terms of x and θ. The solution involves using the central angle to find the fractional amount of the total area: A = (θ / 360) * π * x2 = πx2θ / 360. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 9 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 9TopicGeometry DescriptionThis example features a circle with a radius of 5 units and a shaded arc corresponding to a central angle of 30 degrees. The task is to calculate the length of the shaded arc. The solution involves using the central angle to find the fractional amount of the circumference: Arc Length = (30 / 360) * 2 * π * 5 = 5π / 6. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 8 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 8TopicGeometry DescriptionThis example presents a circle with a radius of 5 units and a shaded sector with a central angle of 30 degrees. The task is to calculate the area of the shaded sector. The solution involves using the central angle to find the fractional amount of the total area: A = (30 / 360) * π * 52 = 25π / 12. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 7 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 7TopicGeometry DescriptionThis example features two concentric circles with radii x and y. The task is to express the area of the shaded region between these circles in terms of x and y. The solution involves subtracting the area of the smaller circle from the area of the larger circle: A = π * x2 - π * y2 = π(x2 - y2). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 6 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 6TopicGeometry DescriptionThis example presents two concentric circles with radii of 5 and y units. The objective is to express the area of the shaded region between these circles in terms of y. The solution involves subtracting the area of the smaller circle from the area of the larger circle: A = π * (5)2 - π * y2 = 25π - πy2 = π(25 - y2). |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 5 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 5TopicGeometry DescriptionThis example features two concentric circles with radii of 5 and 4 units. The task is to calculate the area of the shaded region between these circles. The solution involves subtracting the area of the smaller circle from the area of the larger circle: A = π * (5)2 - π * (4)2 = 25π - 16π = 9π. Concentric circles and shaded regions introduce students to more complex geometric concepts. This example builds upon basic circular area calculations, encouraging students to think about the relationships between different circles and how to find areas of composite shapes. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 4 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 4TopicGeometry DescriptionThis example presents a circle with an unknown radius represented by x. The task is to express the circumference of the circle in terms of x. The solution demonstrates how to use the circumference formula with a variable radius: C = 2 * π * r = 2 * π * x = 2πx. Understanding circular area and circumference is crucial in geometry. This example helps students transition from concrete numerical values to abstract algebraic expressions, fostering a deeper comprehension of the relationship between a circle's radius and its circumference. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 3 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 3TopicGeometry DescriptionThis example introduces a circle with an unknown radius represented by x. The task is to express the area of the circle in terms of x. The solution demonstrates how to use the area formula with a variable radius: A = π * r2 = π * (x)2 = π * x2. Working with variable expressions in geometry helps students transition from concrete to abstract thinking. This example bridges the gap between numerical calculations and algebraic representations, a crucial skill in advanced mathematics. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 2 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 2TopicGeometry DescriptionThis example features a circle with a radius of 5 units. The objective is to calculate the circumference of the circle using the given radius. The solution involves applying the circumference formula: C = 2 * π * r = 2 * π * (5) = 10π. Circular area and circumference calculations are fundamental in geometry. These examples provide students with practical applications of theoretical concepts, helping them understand the relationship between a circle's radius and its circumference. |
Area and Circumference | |
Math Example--Area and Perimeter--Circular Area and Circumference: Example 1 | Math Example--Area and Perimeter--Circular Area and Circumference: Example 1TopicGeometry DescriptionThis example presents a circle with a radius of 5 units. The task is to calculate the area of the circle using the given radius. The solution involves substituting the radius value into the area formula: A = π * r^2 = π * (5)^2 = 25π. Understanding circular area and circumference is integral to mastering geometry. Concepts such as calculating areas and circumferences of circles are fundamental, and exercises like these examples not only provide practice but also deepen the understanding of theoretical concepts in a practical way. |
Area and Circumference | |
Formulas--Circumference of a Circle | Formulas--Circumference of a Circle
The formula for the Circumference of a Circle. This is part of a collection of math formulas. To see the complete collection of formulas, click on this link. Note: The download is a JPG file.Related ResourcesTo see resources related to this topic click on the Related Resources tab above. |
Area and Circumference |